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The relays are shipped from the factory with the maximum torque angle set for five
V).
degrees (I leads
1.
Connect the relay as shown in Figure 128.
2.
Jumper studs 13-14 and studs 15-16 if required.
3.
Put basic reach taps in 1.5 ohm tap.
4.
With restraint taps set for 100 percent, apply 60 volts to relay.
5.
Set current to 15 amperes.
6 .
Turn the phase shifter and determine the two angles at which the left contact
just closes (angle of zero torque).
0
f
ll ows:
a) Add the two angles found above
b) Divide the sum by two.
lower unit.
get the maximum torque angle.
For example:
326 degrees. Adding the two values 52
equals 189 degrees; subtracting 180 degrees equals nine degrees for the angle
of maximum torque.
7.
If studs 13-14 and studs 15-16 are jumpered, the upper rheostat on the unit
should be turned clockwise to make the angle of maximum torque lower; or
counterclockwise to make the angle of maximum torque higher.
8.
If studs 13-14 and studs 15-16 are not jumpered, the upper rheostat on the
unit should be turned counterclockwise to make the angle of maximum torque
lower, and clockwise to make the angle of maximum torque higher.
9.
If the upper rheostat is turned completely counterclockwise, the rheostat
will be at zero ohms, and the angle of maximum torque will be approximately
the same whether studs 13-14 and studs 15-16 are shorted or left unshorted.
This is the angle that determines whether to short studs 13-14 and studs
15-16. For angles of maximum torque below this value, studs 13-14 and studs
15-16 must be jumpered. For angles of maximum torque above this value, studs
13-14 and studs 15-16 should not be shorted.
and 30 degrees.
BASIC R EACH OHMS
When the angle of maximum torque is set for the desired value by the tests
outlined in ANGLE OF MAXIMU M TORQUE ADJUST M ENT, the basic reach should be checked as
011
f
ows:
Turn the phase shifter to set test circuit to angle of maximum reach.
1.
GEK-49778
For a different angle of maximum torque, proceed as f ollows:
This will be the angle of maximum torque for the
For the upper unit, subtract 180 degrees from the value to
Assume the top unit closes its left contact at 52 degrees and
Find the angle of maximum torque as
=
+
378 degrees.
326
This value will be between 26
17
Dividing by two
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