Correction Factors - Beko DRYPOINT RA 200/AC NA Operating Manual

Installation
2.5.

Correction factors

Correction factor for operating pressure changes :
Inlet air pressure psig
barg
Factor (F1)
Correction factor for ambient temperature changes (Air-Cooled):
ºF
Ambient temperature
ºC
Factor (F2)
Correction factor for inlet air temperature changes:
Air temperature ºF
ºC
Factor (F3)
Correction factor for DewPoint changes:
DewPoint ºF
ºC
Factor (F4)
How to find the air flow capacity:
Air flow Nominal Factor
=
X
capacity duty
Example:
An DRYPOINT RA 500 NA has a nominal duty of 500
scfm (849 m3/h). What is the maximum allowable flow
through the dryer under the following operating
conditions:
–
Inlet air pressure = 120 psig (8 barg)
–
Ambient temperature = 105° F (40° C)
–
Inlet air temperature = 105° F (40° C)
–
Pressure DewPoint = 38° F (3° C)
Each item of data has a corresponding numerical factor
as follows:
500
Air flow
= x
capacity
=
348 scfm (591 m
maximum flow rate that the dryer can accept under
these operating conditions.
10
60 80
4 5.5
0.79 0.91
80
27
1.22 1.11
90 100
32 38
1.16 1.00
38
3
1.00
Factor Factor
X X
(F1) (F2) (F3)
1.07 0.89 0.85
x x
3
/h) → This is the
100 120
7 8
1.00 1.07
90 100
32 38
1.00
110 120
43 50
0.85 0.73
41
5
1.09
How to select a suitable dryer for a given duty:
Minimum
Factor
=
Std. air
X
(F4)
flow rate
Example:
The procedure here is to list the operating conditions and
then to locate the corresponding numerical factors:
– Design air flow = 300 scfm (509 m
– Inlet air pressure = 120 psig (8 barg)
– Ambient temperature = 105° F (40° C)
– Inlet air temperature = 105° F (40° C)
– Pressure DewPoint = 38° F (3° C)
In order to select the correct dryer model the required flow
rate is to be divided by the correction factors relating to
above mentioned parameters:
Minimum
1.00
x
=
flow rate
=
432 scfm (734 m
suitable for the conditions above is DRYPOINT RA 500
NA (500 scfm or 849 m3/h - nominal duty).
140 160
10 11
1.13 1.18
105 110
40 43
0.94 0.89
130 140
55 60
0.63 0.54
45
7
1.22
Factor Factor
Design
÷ ÷
(F1) (F2)
air flow
300 1.07 0.89
÷
÷
3
/h) →
DRYPOINT RA 200 – 2500 NA
180 200
12.5 14
1.23 1.27
115 120
45 50
0.83 0.78
150 160
65 70
0.47 0.40
50
10
1.36
Factor Factor
÷ ÷
(F3) (F4)
3
/h)
0.85 1.00
÷
÷
Therefore the model