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Example:
6 HP
LA
LC
LB
1
type
22
● Example of each tubing length
At the time of shipment from the factory, this unit is charged
with enough refrigerant for a tubing length of 50 m.
If the tubing length used will be 50 m or less, no additional
charge will be necessary.
Main tubing
Distribution joint tubing
LA = 40 m
Indoor side
LB = 15 m
1 = 25 m
LC = 10 m
2 = 15 m
Total tubing length = 155 m > 50 m
● Obtain charge amount for each tubing size
Note that the charge amounts per 1 meter are different for
each liquid tubing size.
ø9.52 → LA + LB + LC : 65 m × 0.056 kg/m = 3.64 kg
ø6.35 → 1+ 2+ 3+ 4 : 90 m × 0.026 kg/m = 2.34 kg
Chargeless amount of outdoor unit
Additional refrigerant charge amount is 3.18 kg.
CAUTION
Be sure to check the limit density for the room in which the
indoor unit is installed.
2
3
4
type
type
type
28
36
45
3 = 20 m
4 = 30 m
-2.80 kg
Total 3.18 kg
Checking of limit density
Density limit is determined on the basis of the size of a room
using an indoor unit of minimum capacity. For instance, when
an indoor unit is used in a room (floor area 8.00 m
height 2.7 m = room volume 21.6 m
volume should be 22.5 m
of 9.88 kg (3.18 kg + 6.7 kg). Accordingly, openings such as
louvers are required for this room.
<Determination by calculation>
Overall refrigerant charge amount for the air conditioner: kg
(Minimum room volume for indoor unit: m
3.18 (kg) + 6.7 (kg)
=
21.6 (m
)
3
Therefore, openings such as louvers are required for this room.
2
3
m
m
85
229.5
80
216.0
75
202.5
70
189.0
65
175.5
60
162.0
55
148.5
50
135.0
45
121.5
40
108.0
35
94.5
30
81.0
25
67.5
20
54.0
15
40.5
10
27.0
5
13.5
0
0.0
0
10
17
× ceiling
2
), the minimum room
3
(9.88 kg ÷ 0.44 kg/m
) for refrigerant
3
3
= 0.46 (kg/m
)
0.44 (kg/m
3
3
Range below the
density limit of
0.44 kg/m³
(Countermeasures
not needed)
Range above the
density limit of
0.44 kg/m³
(Countermeasures
needed)
20
30
40
50
60
70
Total amount of refrigerant
)
3
)
80
90 100
kg
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