Table of Contents
Advertisement
Section 11
Testing functionality by secondary injection
It
fs
EQUATION14062 V1 EN-US
∠I
tfs
frequency of I
Expected result: start of the protection function and trip in zone 2 when trip conditions are fulfilled.
The trajectory of the impedance traverses the lens characteristic in zone 1
Preliminary steady state test at 50 Hz
•
Go to Main menu /Test /Function status /Impedance protection /OutOfStep(78,Ucos) /
OOSPPAM(78,Ucos):1 /Outputs to check the available service values of the function block
OOSPPAM.
•
Apply the following three-phase symmetrical quantities (the phase angle is related to phase L1):
V
=
ts
EQUATION14066 V1 EN-US
∠
V
ts
EQUATION14058 V1 EN-US
frequency of V
I
50
s
EQUATION14059 V1 EN-US
∠I
50s
frequency of I
It
fs
EQUATION14062 V1 EN-US
∠I
tfs
frequency of I
•
Check that the service values (VOLTAGE, CURRENT, R(%), X(%)) are according to the injected
quantities and that ROTORANG is close to 3.14 rad. For this particular injection the service values
are:
•
•
•
•
•
Note that these values identify a point inside the lens characteristic in zone 1, that is close to the
boundary between zone 1 and zone 2. The START is issued, but no TRIP is performed.
100
I
1
CTs
10459
I
=
×
=
×
tf
I
9000
CTp
= 180º
= 49.5 Hz
tfs
V
VT s
,
0 9
.
V
0 9 1435
.
×
×
=
×
t RZ
,
1
V
VT p
,
ForwardX
=
=
arctan
arctan
ForwardR
= 50 Hz
ts
1
I
CTs
10459
I
=
×
=
×
50
I
9000
CTp
= 0º
= 50 Hz
50s
I
1
CTs
I
10459
=
×
=
×
tf
9000
I
CTp
= 0º
= 50 Hz
tf
VOLTAGE = 1.29 kV
CURRENT = 20918 A
R = 0.89%
X=6.42%
ROTORANG = -3.04 rad
© 2017 - 2022 Hitachi Energy. All rights reserved
1 162
.
A
=
0 1
.
9 36
.
V
×
=
13 8
.
59 33
.
=
82. . 14°
8 19
.
= .
1 162
A
1 162
.
A
=
1MRK 511 409-UUS Rev. K
(Equation 46)
GUID-12F82DD8-A4CE-48C9-944B-0CF3B3F6C9F9 v1
GUID-AA953F5F-2389-4F05-8BBD-D8DC9AF3B0E4 v1
(Equation 47)
(Equation 48)
(Equation 49)
(Equation 50)
Phasor measurement unit RES670
Commissioning manual
Advertisement
Table of Contents
