Measurement Range And Accuracy; Clinical Measurements: Range And Accuracy - Siemens Acuson S1000 Instructions For Use Manual

Measurement Range and Accuracy

The following tables describe the variability in accuracy for clinical measurements.

Clinical Measurements: Range and Accuracy

Direct
Measurement Range
Distance* 0 – 36 cm
0 – 60 cm
Distance using
SieScape extended
field of view
Trace Area* 0 – 560 cm
Time @ 0 – 9.4 sec
Slow Sweep
Time @ 0 – 4.7 sec
Med Sweep
Time @ 0 – 2.4 sec
Fast Sweep
Velocity 10 – 600 cm/sec
* Also applies to measurements on MPR (slice) quadrants from acquired volumes.
2D-Mode Measurements
2D-mode
Measurements Range or Formula
Distance 0 – 34 cm
Distance Ratio D1/D2
Mean Distance (D1+D2+D3)/3
Ellipse
π{1/2[D1
Circumference
Ellipse Area
π(D1)(D2)/4
Ellipse Volume
(π/6)(D1)(D2)
(D1 = axis of rotation)
Trace Circumference 0 – 85 cm
Trace Area 0 – 450 cm
I n s t r u c t i o n s f o r U s e
Tolerance
Symbol
Tol(D)
Tol(D)
2
Tol(A)
Tol(T) @
Slow Sweep
Tol(T) @
Med Sweep
Tol(T) @
Fast Sweep
Tol(V)
Minimum Value
D-Tol(D)
(D1-Tol(D1))/(D2+Tol(D2))
(D1-Tol(D1)+D2-Tol(D2)+
D3-Tol(D3))/3
2 2 1/2
+D2 ]}
π{1/2[(D1-Tol(D1))
(D2-Tol(D2))
π(D1-Tol(D1))(D2-Tol(D2))/4
2
(π/6)(D1-Tol(D1))(D2-
2
Tol(D2))
D-Tol(D)
2
A-Tol(A)
A p p e n d i x A T e c h n i c a l D e s c r i p t i o n
Tolerance Function or Value (Accuracy)
3% of the distance or 1.5 mm; whichever is
greater assuming 1,540 m/sec speed of sound.
Does not apply to trace tool. Distance tolerance
using trace tool is user-dependent.
Linear transducer: 5% of the distance or 2.5 mm;
whichever is greater assuming 1,540 m/sec
speed of sound.
Curved transducer: 8% of the distance or
2.5 mm; whichever is greater assuming
1,540 m/sec speed of sound.
6% of the area or 1.5 cm
assuming minimal operator error in tracing the
desired object and assuming 1,540 m/sec speed
of sound.
15 msec
7.5 msec
3.8 msec
10% of the velocity or 5 cm/s; whichever is
greater using a J J & A string phantom at
45 degrees ±1 degree.
Maximum Value
D + Tol(D)
(D1+Tol(D1))/(D2-Tol(D2))
(D1+Tol(D1)+D2+
Tol(D2)+D3Tol(D3))/3
2
+ π{1/2[(D1+Tol(D1))
2 1/2
]} (D2+Tol(D2))
π(D1+Tol(D1))
(D2+Tol(D2))/4
(π/6)(D1+Tol(D1))
(D2+Tol(D2))
D+Tol(D)
A+Tol(A)
2
; whichever is greater,
2
+
2 1/2
]}
2
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