Fujitsu AJ 126LELDH Series Design & Technical Manual page 34

¢ Calculation example
 Example 1
Indoor temperature
28°CDB/20°CWB
• Selection of indoor unit
No Item
A-1 Cooling heat load
Indoor unit models
A-2
(Example: AU)
A-3 (TCin)r
A-4 (TCin)d
Compensation coefficient of
A-5
pipe length
A-6 (TCin)e
A-7 ∑(TCin)r
A-8 ∑(TCin)d
1-3. Capacity calculation method
Design conditions
Outdoor temperature
35°CDB
Outdoor
unit
Pipe length (L) = 75 m
Indoor Indoor
unit 1 unit 2
Room 1 Room 2
Room
1 2
kW 6.0 6.0 6.0
AUXK AUXK AUXK
024 024 024
kW 7.1 7.1 7.1
kW 7.7 7.7 7.7
0.90
kW 6.9 6.9 6.9
kW 26.3
kW 28.5
- (02-6) -
Pipe length
75 m
Indoor Indoor
unit 3 unit 4
Room 3 Room 4
3 4 5
2.0 1.5
AUXB AUXB
009 007
Refer to "Indoor units" of
unit and indoor unit lineup"
2.8 2.2
INFORMATION on page 01-1.
Refer to
3.0 2.4
Refer to
2.7 2.2
Height difference
20 m
Outdoor unit higher side
Indoor
unit 5
Room 5
Remark
"Outdoor
Chapter 1. GENERAL
"Cooling capacity table
(Indoor unit)" on page 02-13.
"Capacity compensation
coefficient" on page 02-12.
(A-4) × (A-5)
Sum of A-3
Sum of A-4
1. Model selection and capacity calculation
in