Sizing; Derating; Ambient Temperature Derating, Ip20 - ABB ACS560 Hardware Manual

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Sizing

Drive sizing is based on the rated motor current and power. To achieve the rated motor
power given in the table, the rated current of the drive must be higher than or equal to the
rated motor current. Also the rated power of the drive must be higher than or equal to
compared to the rated motor power. The power ratings are the same regardless of the
supply voltage within one voltage range.
Note:
The nominal values of IN apply to the ambient temperature of 40°C (104°F). Derating is
needed above this temperature.

Derating

The load capacity (I
N
as defined below. In such situations, where full motor power is required, oversize the drive
so that the derated value provides sufficient capacity.
Note:
If several situations are present at a time, the effect of derating for each situation is
cumulative.
Example:
If your application requires continuous 12.0 A of motor current (I
frequency, the supply voltage is 400 V and the drive is situated at 1500 m, calculate the
appropriate drive size requirement as follows:
Switching frequency derating (page
18.18 A, where 0.66 is the derating for 8 kHz switching frequency (frames R0...R3).
Altitude derating (page
m = 0.95. The minimum size required becomes then I
Referring to I in the ratings tables (starting from i484355), drive type ACS560-01-025A-4
N
exceeds the I requirement of 19.24 A.
N
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Ambient temperature derating, IP20

Frame size Temperature range
R0...R8
R0...R8
The output current is calculated by the current given in the rating tables multiplying by the
derating factor (k, as shown in the following figure)
, I , I ; note that I
Ld Hd max
110): The minimum size required is I
110): The derating factor for 1500 m is 1 - 1/10 000 m · (1500 - 1000)
+40°C Below Need no derating
+104°F Below
+40...+50°C Derate 1% for every (1.8°F), derating 1%
+104...+122°F
is not derated) decreases for certain situations,
= 18.18 A / 0.95 = 19.14 A.
N
Action
Technical data 109
) at 8 kHz switching
N
= 12.0 A / 0.66 =
N