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6 FUNCTIONAL TESTS (USER SETTINGS)
The real and imaginary components of Z are given by
2
Z ( )
(
real
cos
POSSEQANG
=
-- -
3
2
Z ( )
(
imag
=
-- -
sin
POSSEQANG
3
The magnitude is then given by:
2
Z ( )
Z
=
real
+
imag
The settings are:
Z
= [________] (Zone magnitude)
1
Z
= [________] (magnitude of Zones 2, 3, and 4)
n
4. Calculate the impedance angle, øZ , for each zone, where øZ is the phase angle of the expression,
POSSEQANG
2
∠
-- -
3
and is given by
Z ( )
imag
∅ Z
arc
tan
=
--------------------- -
Z ( )
real
The settings are
øZ
= [________]° (impedance angle of Zone 1)
1
øZ
= [________]° (impedance angle of Zones 2, 3, and 4)
n
5. Choose the IT test angle (øI) for the zone:
øI
= [________]° (Zone 1)
1
øI
= {________]° (Zone 2)
2
øI
= [________]° (Zone 3)
3
øI
= [________]° (Zone 4)
4
6. Calculate VNOM for each zone by substituting the values of Z
V
= [________] Volts rms (nominal test voltage Zone 1)
NOM 1
V
= [________] Volts rms (nominal test voltage Zone 2)
NOM 2
V
= [________] Volts rms (nominal test voltage Zone 3)
NOM 3
V
= [________] Volts rms (nominal test voltage Zone 4)
NOM 4
If Zone 4 is reversed (Protection Setting 408: Z4DIRECTN = REVERS), remember to add 180°
to both the test angle øI
NOTE
GE Power Management
K
0
)
(
cos
ZERSEQANG
+
------
3
K
)
0
(
+
------
sin
ZERSEQANG
3
2
Z ( )
(eq. 6–23)
K
ZERSEQANG
0
∠
+
------
3
(eq. 6–24)
and the impedance angle øZ
4
LPS-D Line Protection System
6.5 ZONE REACH TESTS
)
(eq. 6–21)
)
(eq. 6–22)
, Z , øZ , and øI into Equation 6–19 or 6–20.
R
.
4
6
6-
13
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