ABB IRC5 Product Manual page 47

Cabinet cooling
If the cabinet where the IRC5 Panel Mounted Controller is mounted needs cooling
depends on the power dissipation and the surface area of the cabinet. A heat test
is necessary to get any exact answers. A rough estimation can be made using the
following calculations.
The drive system efficiency is roughly 90%, so the power loss in the drive system
is at least near 10%. Note that the power loss in the drive system will increase
significantly if the motion cycle contains many frequent and sharp decelerations,
which cause very high bleeder power loss. Other equipment in the PMC typically
generates another 240W power loss.
For example, a customer RAPID program that creates 2000W output power may
generate a power loss of 220W in the drive system. Total power loss is then
approximately 460W.
The natural convection from a sheet metal cabinet is calculated as:
Q
A = Enclosure area (m
k = Heat transfer coefficient (W/m
sheet cabinet
ΔT=Ti-Tu = Temperature difference (K)
If the natural convection of the enclosure is to small, cooling equipment is needed
with cooling capacity according to following formula:
Q
Q
Product manual - IRC5 Panel Mounted Controller
3HAC047137-001 Revision: AB
Q =A*k* T
s
= Heat emitted by the enclosure surface (W)
s
2
)
Q = Q - Q
e v s
= Required cooling output from the cooling unit
e
= Installed heat loss
v
© Copyright 2007-2024 ABB. All rights reserved.
2 Installation and commissioning
2.3.1 Unpacking the controller
2
K), where k is approximately 5.5 for a metal
Continued
47