Transmission Delay Time Calculation Example - Mitsubishi Electric MELSEC Q Series Reference Manual

7.3.2

Transmission delay time calculation example

This section provides a calculation example of the cyclic transmission delay.
(1) Transmission delay time in a single network system
(a) System configuration and conditions
CPU module
Total number of stations per network
Total link device points
Sequence scan time
File register
Interlink transmission
Transient transmission
Station-based block data assurance
CC-Link IE Controller Network module
Faulty station
(b) Link scan time (
LS = [KB + (N × 56) + {LB + LY + (LW × 16)  8 × 0.016 + (NT × T × 30)]  1000 + Nc [ms]
= [1100 + (8 × 56) + {1024 + 0 + (1024 × 16)}  8 × 0.016 + (0 × 2 × 30)]  1000
= 1.58 [ms]
(c) Link refresh time (
(1) Sending-side link refresh time, receiving-side link refresh time
T, R
252
Item
Page 244, Section 7.1)
Page 245, Section 7.2)
-3 -3
= 130 × 10 + 0.41 × 10
= 0.80 [ms]
Q06HCPU
8 stations
LB/LW 1024 points for each
LX/LY 0 point
SB/SW 512 points for each
1ms
None
None
None
Assured
Installed to slot 0 of main base unit
None
× {(1024 + 0 + 0 + 512)  16 + 1024 + 512} + 0 + 0
Description